Question

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Correct option is

Let the $C.P$ of each clock be $Rs.x.$

Then $C.P$ of $90$ clocks $=Rs.90x.$

By using the given information,

$(100110 ×40x)+(100120 ×50x)−(100115 ×90x)=40$

$⇒44x+60x−103.5x=40$

$⇒0.5x=40$

$⇒x=80$

So, the $C.P$ of each clock is equal to $Rs.80.$

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