The slope of any line perpendicular to L must be -7/13.

The line through (6,-5) and (-7,2) has slope [2-(-5)]/(-7-6) = -7/13.

Trinity C.

asked • 07/23/17(-5,-7) (2,6)

(6,-5) (-7,2)

(-8,-7) (2,6)

(12,-3) (-7,4)

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The slope of any line perpendicular to L must be -7/13.

The line through (6,-5) and (-7,2) has slope [2-(-5)]/(-7-6) = -7/13.

Michael A. answered • 07/23/17

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You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:

m = (y_{2} - y_{1})/(x_{2} - x_{1})

Consider the second set of coordinates.

(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13

The second set of coordinates satisfy the condition.

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